Consider the phase diagram of the Fe-Fe3C system shown in Figure 7.1. Starting of this diagram,... 1 answer below »

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Consider the phase diagram of the Fe-Fe3C system shown in Figure 7.1. Starting

of this diagram, calculate:

(a) The quantities (in g) of ferrite, cementite and perlite (... perlite, remember, is not a

phase, but a microstructure ...) present in a system consisting of 1 kg of steel with 0.5

% C (by mass) at 725 °C.

(b) The quantities (in g) of ferrite, cementite and perlite (... perlite, remember, is not a

phase, but a microstructure ...) present in a system consisting of 1 kg of steel with 0.9

% C (by mass) at 725°C

Description: 1600
1538°C
8
1495°C
1400
L
1394°C
Y+L
1200
1148°C
7. Austenite
2.11
4.30
Temperature (°C)
1000
Y+ FeẠC
912°C
800 a
+
7
727°C

Consider that the graphs presented in Figure 7.2 are valid to represent the

mechanical properties at room temperature of steels whose compositions are

mentioned in items (a) and (b) - that is, steels with 0.5% C and 0.9% C compositions (both

mass compositions).

Description: Percent Fesc
6 9
0
3
sd 01
12
15
Percent Fez
6
9
0
12
15
1200
-
120
Pearlite + ferrite
+
Pearlite
Fec
Pearlite forrit
-
80
11

(c) What would be the tensile strength limit values , yield (strength) and ductility (elongation) for these two steels?

(d) Explain the differences observed in the values ​​determined in item ©, taking into account based on the relative percentages of the phases and their respective chemical compositions.

 

1 Approved Answer

Jones G
4 Ratings (8 Votes)
To calculate the quantities of ferrite, cementite, and perlite in a given steel system at 725°C, we'll use the lever rule and phase diagram shown in Figure 7.1. (a) For a steel with 0.5% C at 725°C: Given: - Mass of steel (m) = 1 kg = 1000 g - Carbon composition (C) = 0.5% = 0.005 (mass fraction) - Temperature (T) = 725°C 1. First, locate the point on the phase diagram corresponding to 0.5% C at 725°C. 2. Using the...

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